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| & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g + 2 d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \\ | | & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g + 2 d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \\ |
| & = 2 d^{\prime} \left( d^{\prime} - x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \right) \\ | | & = 2 d^{\prime} \left( d^{\prime} - x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \right) \\ |
− | \left( \frac{q}{k} \right)^2
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− | & = 2 \left( 1 - \frac{x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g )}{d^{\prime} } \right)
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− | \end{alignat}
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− | </math>
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− |
| |
− | ====Check of Total Magnitude #2: Doesn't work====
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− | We define:
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− | ::<math>
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− | \begin{alignat}{2}
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− | d^{\prime} & = \sqrt{x^2 + d^2 + z^2} = \| \mathbf{v}_1 \| \\
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− | ( v_{2y} ) & = ( d \cos \theta_g - z \sin \theta_g ) \\
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− | ( v_{2y} )^2 & = ( d \cos \theta_g - z \sin \theta_g )^2 \\
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− | & = d^2 \cos^2 \theta_g - 2dz \cos \theta_g \sin\theta_g + z^2 \sin^2 \theta_g
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− | \end{alignat}
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− | </math>
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− |
| |
− | And calculate:
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− | :<math>
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− | \begin{alignat}{2}
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− | q^2 & = [ (q_x)^2 + (q_y)^2 + (q_z)^2 ] \\
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− | \left ( \frac{q}{k} \right )^2 d^{\prime 2}
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− | & = \begin{alignat}{2} [ & \left( x \cos \phi_g -\sin \phi_g ( d \cos \theta_g - z \sin \theta_g ) \right)^2 \\ & + \left( x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) - d^{\prime} \right)^2 \\ & + \left( d \sin \theta_g + z \cos \theta_g \right)^2 ] \end{alignat} \\
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− |
| |
− | & = \begin{alignat}{2} [
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− | & \left( x \cos \phi_g -\sin \phi_g ( v_{2y} ) \right)^2 \\
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− | & + \left( x \sin \phi_g + \cos \phi_g ( v_{2y} ) - d^{\prime} \right)^2 \\
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− | & + \left( d \sin \theta_g + z \cos \theta_g \right)^2 ] \end{alignat} \\
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− |
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− | & = \begin{alignat}{2} [
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− | & x^2 \cos^2 \phi_g - 2 x \cos \phi_g \sin \phi_g ( v_{2y} ) + \sin^2 \phi_g ( v_{2y} )^2 \\
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− | & + x^2 \sin^2 \phi_g + x \sin \phi_g \cos \phi_g ( v_{2y} ) - d^{\prime} x \sin \phi_g \\
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− | & + x \sin \phi_g \cos \phi_g ( v_{2y} ) + \cos^2 \phi_g ( v_{2y} )^2 - d^{\prime} \cos \phi_g ( v_{2y} ) \\
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− | & - d^{\prime} x \sin \phi_g - d^{\prime} \cos \phi_g ( v_{2y} ) + d^{\prime 2} \\
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− | & + d^2 \sin^2 \theta_g + 2 d z \sin \theta_g \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\
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− | \end{alignat}
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− | </math>
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− | Grouping and rearranging:
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− | :<math>
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− | \begin{alignat}{2}
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− | \left ( \frac{q}{k} \right )^2 d^{\prime 2}
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− | & = \begin{alignat}{2} [
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− | & x^2 + ( v_{2y} )^2 \\
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− | & - 2 d^{\prime} x \sin \phi_g \\
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− | & - 2 d^{\prime} \cos \phi_g ( v_{2y} ) \\
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− | & + d^{\prime 2} \\
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− | & + d^2 \sin^2 \theta_g + 2 d z \sin \theta_g \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\
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− |
| |
− | & = \begin{alignat}{2} [
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− | & d^{\prime 2} + x^2 + ( d^2 \cos^2 \theta_g - 2dz \cos \theta_g \sin\theta_g + z^2 \sin^2 \theta_g ) \\
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− | & - 2 d^{\prime} x \sin \phi_g - 2 d^{\prime} \cos \phi_g ( v_{2y} ) \\
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− | & + d^2 \sin^2 \theta_g + 2 d z \sin \theta_g \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\
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− |
| |
− | & = \begin{alignat}{2} [
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− | & d^{\prime 2} + x^2 + d^2 + z^2 \\
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− | & - 2 d^{\prime} x \sin \phi_g - 2 d^{\prime} \cos \phi_g ( v_{2y} ) ] \end{alignat} \\
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− |
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− | & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g - 2 d^{\prime} \cos \phi_g ( v_{2y} )\\
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− |
| |
− | & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g - 2 d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \\
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− | & = 2 d^{\prime} \left( d^{\prime} - x \sin \phi_g - \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \right) \\
| |
| \left( \frac{q}{k} \right)^2 | | \left( \frac{q}{k} \right)^2 |
| & = 2 \left( 1 - \frac{x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g )}{d^{\prime} } \right) | | & = 2 \left( 1 - \frac{x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g )}{d^{\prime} } \right) |
| \end{alignat} | | \end{alignat} |
| </math> | | </math> |