Talk:Geometry:WAXS 3D
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Check of Total Magnitude #2: Doesn't work
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Check of Total Magnitude #1: Doesn't work
(
q
k
)
2
d
′
2
=
[
(
x
cos
ϕ
g
−
sin
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
)
2
+
(
x
sin
ϕ
g
+
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
−
d
′
)
2
+
(
d
sin
θ
g
+
z
cos
θ
g
)
2
]
=
[
x
2
cos
2
ϕ
g
−
x
cos
ϕ
g
sin
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
+
sin
2
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
2
+
x
2
sin
2
ϕ
g
+
x
sin
ϕ
g
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
−
d
′
x
sin
ϕ
g
+
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
x
sin
ϕ
g
+
cos
2
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
2
−
d
′
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
−
d
′
x
sin
ϕ
g
−
d
′
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
+
d
′
2
+
d
2
sin
2
θ
g
+
2
d
sin
θ
g
z
cos
θ
g
+
z
2
cos
2
θ
g
]
=
[
x
2
cos
2
ϕ
g
−
x
cos
ϕ
g
sin
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
+
sin
2
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
2
+
x
2
sin
2
ϕ
g
+
2
x
sin
ϕ
g
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
−
2
d
′
x
sin
ϕ
g
+
cos
2
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
2
−
2
d
′
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
+
d
′
2
+
d
2
sin
2
θ
g
+
2
d
sin
θ
g
z
cos
θ
g
+
z
2
cos
2
θ
g
]
=
[
x
2
−
x
sin
ϕ
g
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
+
(
d
cos
θ
g
−
z
sin
θ
g
)
2
+
2
x
sin
ϕ
g
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
−
2
d
′
x
sin
ϕ
g
−
2
d
′
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
+
d
′
2
+
d
2
sin
2
θ
g
+
2
d
z
sin
θ
g
cos
θ
g
+
z
2
cos
2
θ
g
]
=
[
x
2
+
d
2
cos
2
θ
g
−
2
d
z
cos
θ
g
sin
θ
g
+
z
2
sin
2
θ
g
+
(
−
x
sin
ϕ
g
cos
ϕ
g
+
2
x
sin
ϕ
g
cos
ϕ
g
−
2
d
′
cos
ϕ
g
)
(
d
cos
θ
g
−
z
sin
θ
g
)
−
2
d
′
x
sin
ϕ
g
+
d
′
2
+
d
2
sin
2
θ
g
+
2
d
z
sin
θ
g
cos
θ
g
+
z
2
cos
2
θ
g
]
=
[
d
′
2
+
x
2
+
d
2
+
z
2
−
2
d
z
cos
θ
g
sin
θ
g
+
(
x
sin
ϕ
g
cos
ϕ
g
−
2
d
′
cos
ϕ
g
)
(
d
cos
θ
g
−
z
sin
θ
g
)
+
2
d
z
sin
θ
g
cos
θ
g
−
2
d
′
x
sin
ϕ
g
]
=
2
d
′
2
−
2
d
′
x
sin
ϕ
g
+
(
x
sin
ϕ
g
cos
ϕ
g
−
2
d
′
cos
ϕ
g
)
(
d
cos
θ
g
−
z
sin
θ
g
)
=
2
d
′
2
−
2
d
′
x
sin
ϕ
g
+
(
x
sin
ϕ
g
−
2
d
′
)
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
=
?
=
?
=
2
d
′
2
−
2
d
′
x
sin
ϕ
g
+
2
d
′
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
=
2
d
′
(
d
′
−
x
sin
ϕ
g
+
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
)
(
q
k
)
2
=
2
(
1
−
x
sin
ϕ
g
+
cos
ϕ
g
(
d
cos
θ
g
−
z
sin
θ
g
)
d
′
)
{\displaystyle {\begin{alignedat}{2}\left({\frac {q}{k}}\right)^{2}d^{\prime 2}&={\begin{alignedat}{2}[&\left(x\cos \phi _{g}-\sin \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\right)^{2}\\&+\left(x\sin \phi _{g}+\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})-d^{\prime }\right)^{2}\\&+\left(d\sin \theta _{g}+z\cos \theta _{g}\right)^{2}]\end{alignedat}}\\&={\begin{alignedat}{2}[&x^{2}\cos ^{2}\phi _{g}-x\cos \phi _{g}\sin \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})+\sin ^{2}\phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})^{2}\\&+x^{2}\sin ^{2}\phi _{g}+x\sin \phi _{g}\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})-d^{\prime }x\sin \phi _{g}\\&+\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})x\sin \phi _{g}+\cos ^{2}\phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})^{2}-d^{\prime }\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\\&-d^{\prime }x\sin \phi _{g}-d^{\prime }\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})+d^{\prime 2}\\&+d^{2}\sin ^{2}\theta _{g}+2d\sin \theta _{g}z\cos \theta _{g}+z^{2}\cos ^{2}\theta _{g}]\end{alignedat}}\\&={\begin{alignedat}{2}[&x^{2}\cos ^{2}\phi _{g}-x\cos \phi _{g}\sin \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})+\sin ^{2}\phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})^{2}\\&+x^{2}\sin ^{2}\phi _{g}+2x\sin \phi _{g}\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})-2d^{\prime }x\sin \phi _{g}\\&+\cos ^{2}\phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})^{2}-2d^{\prime }\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})+d^{\prime 2}\\&+d^{2}\sin ^{2}\theta _{g}+2d\sin \theta _{g}z\cos \theta _{g}+z^{2}\cos ^{2}\theta _{g}]\end{alignedat}}\\&={\begin{alignedat}{2}[&x^{2}-x\sin \phi _{g}\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})+(d\cos \theta _{g}-z\sin \theta _{g})^{2}\\&+2x\sin \phi _{g}\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})-2d^{\prime }x\sin \phi _{g}\\&-2d^{\prime }\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})+d^{\prime 2}\\&+d^{2}\sin ^{2}\theta _{g}+2dz\sin \theta _{g}\cos \theta _{g}+z^{2}\cos ^{2}\theta _{g}]\end{alignedat}}\\&={\begin{alignedat}{2}[&x^{2}+d^{2}\cos ^{2}\theta _{g}-2dz\cos \theta _{g}\sin \theta _{g}+z^{2}\sin ^{2}\theta _{g}\\&+(-x\sin \phi _{g}\cos \phi _{g}+2x\sin \phi _{g}\cos \phi _{g}-2d^{\prime }\cos \phi _{g})(d\cos \theta _{g}-z\sin \theta _{g})\\&-2d^{\prime }x\sin \phi _{g}\\&+d^{\prime 2}\\&+d^{2}\sin ^{2}\theta _{g}+2dz\sin \theta _{g}\cos \theta _{g}+z^{2}\cos ^{2}\theta _{g}]\end{alignedat}}\\&={\begin{alignedat}{2}[&d^{\prime 2}+x^{2}+d^{2}+z^{2}-2dz\cos \theta _{g}\sin \theta _{g}\\&+(x\sin \phi _{g}\cos \phi _{g}-2d^{\prime }\cos \phi _{g})(d\cos \theta _{g}-z\sin \theta _{g})\\&+2dz\sin \theta _{g}\cos \theta _{g}-2d^{\prime }x\sin \phi _{g}]\end{alignedat}}\\&=2d^{\prime 2}-2d^{\prime }x\sin \phi _{g}+(x\sin \phi _{g}\cos \phi _{g}-2d^{\prime }\cos \phi _{g})(d\cos \theta _{g}-z\sin \theta _{g})\\&=2d^{\prime 2}-2d^{\prime }x\sin \phi _{g}+(x\sin \phi _{g}-2d^{\prime })\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\\&=?\\&=?\\&=2d^{\prime 2}-2d^{\prime }x\sin \phi _{g}+2d^{\prime }\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\\&=2d^{\prime }\left(d^{\prime }-x\sin \phi _{g}+\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\right)\\\left({\frac {q}{k}}\right)^{2}&=2\left(1-{\frac {x\sin \phi _{g}+\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})}{d^{\prime }}}\right)\end{alignedat}}}
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