Difference between revisions of "Talk:DWBA"

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(Breaking into components)
(Breaking into components)
Line 118: Line 118:
 
\begin{align}
 
\begin{align}
 
I_d(q_{z})  
 
I_d(q_{z})  
   & = [ T_i^2T_f^2 + R_i^2 + R_f^2 ] I_{Tc}(q_z) + [ T_i^2 R_f^2 + R_i^2 + T_f^2 ] I_{Rc}(q_z) \\
+
   & = [ | T_i T_f|^2 + |R_i R_f|^2 ] I_{Tc}(q_z) + [ |T_i R_f|^2 + |R_i T_f|^2 ] I_{Rc}(q_z) \\
 
   & = |Tc|^2 I_{Tc}(q_z) + |Rc|^2 I_{Rc}(q_z) \\
 
   & = |Tc|^2 I_{Tc}(q_z) + |Rc|^2 I_{Rc}(q_z) \\
 
\end{align}
 
\end{align}

Revision as of 18:28, 12 March 2018

DWBA Equation in thin film

Using the notation for compactness, the DWBA equation inside a thin film can be written:

Expansion

Terms

If one expands the of the DWBA, one obtains 16 terms:

Equation

The equation can thus be expanded as:

Simplification

We can rearrange to:


We can rewrite in a more compact form using the notation and :

Breaking into components

The experimental data can be broken into contributions from the transmitted channel and reflected channel :

We define the ratio between the channels to be:

Such that one can compute the two components from:

and: