Difference between revisions of "Talk:Geometry:WAXS 3D"

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(Check)
(Check)
Line 10: Line 10:
 
</math>
 
</math>
  
And solve:
+
And calculate:
 
:<math>
 
:<math>
 
\begin{alignat}{2}
 
\begin{alignat}{2}
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       & + \left( d \sin \theta_g + z \cos \theta_g \right)^2  ] \end{alignat}  \\
 
       & + \left( d \sin \theta_g + z \cos \theta_g \right)^2  ] \end{alignat}  \\
  
 +
    & = \begin{alignat}{2} [
 +
      & x^2 \cos^2 \phi_g - x \cos \phi_g \sin \phi_g ( v_{2y} ) + \sin^2 \phi_g ( v_{2y} )^2  \\
 +
      & + x^2 \sin^2 \phi_g + x \sin \phi_g \cos \phi_g ( v_{2y} ) - d^{\prime} x \sin \phi_g \\
 +
      & + x \sin \phi_g \cos \phi_g ( v_{2y} ) + \cos^2 \phi_g ( v_{2y} )^2 - d^{\prime} \cos \phi_g ( v_{2y} ) \\
 +
      & - d^{\prime} x \sin \phi_g - d^{\prime} \cos \phi_g ( v_{2y} ) + d^{\prime 2} \\
 +
      & + d^2 \sin^2 \theta_g + d z \sin \theta_g \cos \theta_g + z^2 \cos^2 \theta_g  ] \end{alignat}  \\
 +
\end{alignat}
 +
</math>
 +
Grouping and rearranging:
 +
:<math>
 +
\begin{alignat}{2}
 +
\left ( \frac{q}{k} \right )^2 d^{\prime 2}
 
     & = \begin{alignat}{2} [  
 
     & = \begin{alignat}{2} [  
 
       & x^2 \cos^2 \phi_g - x \cos \phi_g \sin \phi_g ( v_{2y} ) + \sin^2 \phi_g ( v_{2y} )^2  \\  
 
       & x^2 \cos^2 \phi_g - x \cos \phi_g \sin \phi_g ( v_{2y} ) + \sin^2 \phi_g ( v_{2y} )^2  \\  

Revision as of 16:14, 13 January 2016

Check

We define:

And calculate:

Grouping and rearranging: