Difference between revisions of "Ewald sphere"

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===Reflectivity===
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====Reflectivity====
 
Consider for a moment that the ''q''-vector is confined to the <math>(q_y,q_z)</math> plane:
 
Consider for a moment that the ''q''-vector is confined to the <math>(q_y,q_z)</math> plane:
 
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Revision as of 10:31, 24 June 2014

The Ewald sphere is the surface, in reciprocal-space, that all experimentally-observed scattering arises from. (Strictly, only the elastic scattering comes from the Ewald sphere; inelastic scattering is so-called 'off-shell'.) A peak observed on the detector indicates that a reciprocal-space peak is intersecting with the Ewald sphere.

Mathematics

In TSAXS of an isotropic sample, we only probe the magnitude (not direction) of the momentum transfer:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle q = \frac{4 \pi}{\lambda} \sin(\theta) }

Where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2\theta} is the full scattering angle. In GISAXS, we must take into account the vector components:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} q_x & = \frac{2 \pi}{\lambda} \cos(\alpha_f)\sin(2\theta_f) \\ q_y & = \frac{2 \pi}{\lambda} \left[ \cos(\alpha_f)\cos(2\theta_f) - \cos(\alpha_f) \right ]\\ q_x & = \frac{2 \pi}{\lambda} \left[ \sin(\alpha_f) + \sin(\alpha_f) \right ] \end{alignat} }

Derivation

Definitions

Consider reciprocal-space in the incident beam coordinate system: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (q_x,q_y,q_z)} . The incident beam is the vector Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{k_i} = \langle 0,-k,0 \rangle} , where:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle k = \frac{2 \pi}{\lambda}}

where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lambda} is, of course, the wavelength of the incident beam. An elastic scattering event has an outgoing momentum (Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{k_f}} ) of the same magnitude as the incident radiation (i.e. Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\mathbf{k_i}| = |\mathbf{k_f}| = k} ). Consider a momentum vector, and resultant momentum transfer, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{q}} , of:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} \mathbf{k_f} & = \begin{bmatrix} 0 \\ -k \cos(2 \theta_s) \\ +k \sin(2 \theta_s) \rangle \\ \end{bmatrix} \\ \mathbf{q} & = \mathbf{k_f} - \mathbf{k_i} \\ & = \begin{bmatrix} 0 \\ -k \cos(2 \theta_s) \\ +k \sin(2 \theta_s) \\ \end{bmatrix} - \begin{bmatrix} 0 \\ -k \\ 0 \\ \end{bmatrix} \\ & = \begin{bmatrix} 0 \\ k( 1 -\cos(2 \theta_s) ) \\ +k \sin(2 \theta_s) \rangle \\ \end{bmatrix} \\ & = \begin{bmatrix} 0 \\ 2 k \sin^2(\theta_s) \\ 2 k \sin(\theta_s) \cos(\theta_s) \rangle \\ \end{bmatrix} \\ \end{alignat} }

The magnitude of the momentum transfer is thus:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} q & = | \mathbf{q} | \\ & = \sqrt{ [2 k \sin^2(\theta_s))]^2 + [ 2 k \sin(\theta_s)\cos(\theta_s)]^2 } \\ & = \sqrt{ 4k^2 [ \sin^4(\theta_s) + \sin^2(\theta_s)\cos^2(\theta_s)] } \\ & = 2 k \sqrt{ \sin^4(\theta_s) + \sin^2(\theta_s)\cos^2(\theta_s) } \\ & = 2 k \sqrt{ \sin^2(\theta_s)} \\ & = 2 k \sin(\theta_s) \\ & = \frac{4 \pi}{\lambda} \sin(\theta_s) \\ \end{alignat} }

where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2 \theta_s} is the full scattering angle. The Ewald sphere is centered about the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (0,-k,0)} and thus has the equation:

TSAXS

In conventional SAXS, the signal of interest is isotropic: i.e. we only care about Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\mathbf{q}| = q} , and not the individual (directional) components Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (q_x,q_y,q_z)} . In such a case we use the form of q derived above:

In the more general case of probing an anisotropic material (e.g. CD-SAXS), one must take into account the full q-vector, and in particular the relative orientation of the incident beam and the sample: i.e. the relative orientation of the Ewald sphere and the reciprocal-space.

GISAXS

Now let us assume that the incident beam strikes a thin film mounted to a substrate. The incident beam is in the grazing-incidence geometry (e.g. GISAXS, and we denote the angle between the incident beam and the film surface as . The reciprocal-space of the sample is thus rotated by Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \theta_i} with respect to the beam reciprocal-space coordinates. We convert to the sample's reciprocal coordinate space; still denoted by Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (Q_x,Q_y,Q_z)} . The equation of the Ewald sphere becomes (the center of the sphere is at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle 0,k \cos\theta_i, k \sin\theta_i \rangle} ):

Reflectivity

Consider for a moment that the q-vector is confined to the Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (q_y,q_z)} plane:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} \mathbf{q} = \begin{bmatrix} 0 \\ - q \sin(\alpha_f - \alpha_i) \\ + q \cos(\alpha_f - \alpha_i) \\ \end{bmatrix} \end{alignat} }

Obviously the specular condition is when Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \alpha_f=\alpha_i} , in which case one obtains:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} \mathbf{q} = \begin{bmatrix} 0 \\ 0 \\ + q \\ \end{bmatrix} \end{alignat} }

That is, reflectivity is inherently only probing the out-of-plane (Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle q_z} ) component:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle q_z = \frac{4 \pi}{\lambda} \sin \alpha_i }

Out-of-plane scattering only

Simplifying the above expression yields:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} \mathbf{q} = \begin{bmatrix} 0 \\ - q \sin(\alpha_f - \alpha_i) \\ + q \cos(\alpha_f - \alpha_i) \\ \end{bmatrix} \end{alignat} }

Literature

Conceptual Understanding of Ewald sphere

Equations of GISAXS Geometry