Difference between revisions of "Absorption length"
KevinYager (talk | contribs) (→Calculating) |
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\sigma = 2 r_e \lambda f_2 | \sigma = 2 r_e \lambda f_2 | ||
</math> | </math> | ||
− | Where ''λ'' is the x-ray wavelength, and ''r<sub>e</sub>'' is the classical electron radius. | + | Where ''λ'' is the x-ray wavelength, and ''r<sub>e</sub>'' is the classical electron radius. The '''attenuation coefficient''' is given by: |
+ | :<math> | ||
+ | \begin{alignat}{2} | ||
+ | \mu & = \frac{\rho N_a}{m_a} \sigma \\ | ||
+ | & = \frac{\rho N_a}{m_a} \2 r_e \lambda f_2 | ||
+ | \end{alignat} | ||
+ | </math> | ||
+ | where ''ρ'' is density, ''N<sub>a</sub>'' is the Avogadro constant, and ''m<sub>a</sub>'' is the atomic molar mass. Note that the '''mass attenuation coefficient''' is simply <math>\mu/\rho</math>. | ||
==See Also== | ==See Also== |
Revision as of 13:47, 6 June 2014
The absorption length or attenuation length in x-ray scattering is the distance over which the x-ray beam is absorbed. By convention, the absorption length ϵ is defined as the distance into a material where the beam flux has dropped to 1/e of its incident flux.
Absorption
The absorption follows a simple Beer-Lambert law:
The attenuation coefficient (or absorption coefficient) is simply the inverse of the absorption length;
Calculating
The absorption length arises from the imaginary part of the atomic scattering factor, f2. It is closely related to the absorption cross-section, and the mass absorption coefficient. Specifically, the atomic photoabsorption cross-section can be computed via:
Where λ is the x-ray wavelength, and re is the classical electron radius. The attenuation coefficient is given by:
- Failed to parse (unknown function "\begin{alignat}"): {\displaystyle \begin{alignat}{2} \mu & = \frac{\rho N_a}{m_a} \sigma \\ & = \frac{\rho N_a}{m_a} \2 r_e \lambda f_2 \end{alignat} }
where ρ is density, Na is the Avogadro constant, and ma is the atomic molar mass. Note that the mass attenuation coefficient is simply .