Difference between revisions of "Ewald sphere"

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(Definitions)
(Definitions)
Line 22: Line 22:
 
: <math>
 
: <math>
 
\begin{alignat}{2}
 
\begin{alignat}{2}
\mathbf{k_f} & = \langle 0,-k \cos(2 \theta_s), +k \sin(2 \theta_s) \rangle \\
+
\mathbf{k_f} & = \begin{bmatrix}
 +
    0 \\
 +
    -k \cos(2 \theta_s) \\
 +
    +k \sin(2 \theta_s) \rangle \\
 +
\end{bmatrix} \\
 
\mathbf{q}  & = \mathbf{k_f} - \mathbf{k_i} \\
 
\mathbf{q}  & = \mathbf{k_f} - \mathbf{k_i} \\
    & =  \langle 0,-k \cos(2 \theta_s), +k \sin(2 \theta_s) \rangle - \langle 0,-k,0 \rangle\\
+
& = \begin{bmatrix}
    & =  \langle 0,k(1-\cos(2 \theta_s)), +k \sin(2 \theta_s) \rangle \\
+
    0 \\
    & =  \langle 0, 2 k \sin^2(\theta_s)), 2 k \sin(\theta_s) \cos(\theta_s) \rangle \\
+
    -k \cos(2 \theta_s) \\
 +
    +k \sin(2 \theta_s) \\
 +
\end{bmatrix}
 +
-  
 +
\begin{bmatrix}
 +
    0 \\
 +
    -k \\
 +
    0 \\
 +
\end{bmatrix} \\
 +
& = \begin{bmatrix}
 +
    0 \\
 +
    k( 1 -\cos(2 \theta_s) ) \\
 +
    +k \sin(2 \theta_s) \rangle \\
 +
\end{bmatrix} \\
 +
& = \begin{bmatrix}
 +
    0 \\
 +
    2 k \sin^2(\theta_s) \\
 +
    2 k \sin(\theta_s) \cos(\theta_s) \rangle \\
 +
\end{bmatrix} \\
 +
\end{alignat}
 +
</math>
 +
The magnitude of the momentum transfer is thus:
 +
: <math>
 +
\begin{alignat}{2}
 
q & = | \mathbf{q} | \\
 
q & = | \mathbf{q} | \\
 
     & =  \sqrt{ [2 k \sin^2(\theta_s))]^2 + [ 2 k \sin(\theta_s)\cos(\theta_s)]^2 } \\
 
     & =  \sqrt{ [2 k \sin^2(\theta_s))]^2 + [ 2 k \sin(\theta_s)\cos(\theta_s)]^2 } \\

Revision as of 09:06, 24 June 2014

The Ewald sphere is the surface, in reciprocal-space, that all experimentally-observed scattering arises from. (Strictly, only the elastic scattering comes from the Ewald sphere; inelastic scattering is so-called 'off-shell'.) A peak observed on the detector indicates that a reciprocal-space peak is intersecting with the Ewald sphere.

Mathematics

In TSAXS of an isotropic sample, we only probe the magnitude (not direction) of the momentum transfer:

Where is the full scattering angle. In GISAXS, we must take into account the vector components:

Derivation

Definitions

Consider reciprocal-space in the incident beam coordinate system: . The incident beam is the vector , where:

where is, of course, the wavelength of the incident beam. An elastic scattering event has an outgoing momentum () of the same magnitude as the incident radiation (i.e. ). Consider a momentum vector, and resultant momentum transfer, , of:

The magnitude of the momentum transfer is thus:

where is the full scattering angle. The Ewald sphere is centered about the point and thus has the equation:

TSAXS

In conventional SAXS, the signal of interest is isotropic: i.e. we only care about , and not the individual (directional) components . In such a case we use the form of q derived above:

In the more general case of probing an anisotropic material (e.g. CD-SAXS), one must take into account the full q-vector, and in particular the relative orientation of the incident beam and the sample: i.e. the relative orientation of the Ewald sphere and the reciprocal-space.

GISAXS

Now let us assume that the incident beam strikes a thin film mounted to a substrate. The incident beam is in the grazing-incidence geometry (e.g. GISAXS, and we denote the angle between the incident beam and the film surface as . The reciprocal-space of the sample is thus rotated by with respect to the beam reciprocal-space coordinates. We denote the sample's reciprocal coordinate system by uppercase, , and note that the equation of the Ewald sphere becomes (the center of the sphere is at ):

Literature

Conceptual Understanding of Ewald sphere

Equations of GISAXS Geometry